How many 176 resistors

WebApr 4, 2016 · also note that resistors often have a rated voltage of 200V, you might want to use 2 50k resistors, or dissipated less power and use way higher values, Megaohms might be feasable (or the mentioned C-R divider) – Christian Apr 1, 2016 at 10:58 Show 3 more comments 2 Answers Sorted by: 1 * Danger * WebHow many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line?Welcome to our channel, hope you will get sufficient information from o... Q10.

How many 176 Ω resistors (in parallel) are required to …

WebSep 28, 2024 · The resistance of a conductor is directly proportional to the length of the conductor. The resistance of the metallic wire, when it is cut into ten parts of equal length is r = \frac {R} {10} Two such pieces when joined in series, the equivalent resistance of these two parts = r + r = 2r = \frac {2R} {10} WebHow many 176 Ω resistors (in parallel) are required to carry 5A on a 220V line? Class 12. cummings jewish center https://desdoeshairnyc.com

How many 176 Ω resistors (in parallel) are required to …

WebApr 5, 2024 · How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Suppose n resistors of 176 Ω are connected in parallel. 1/R = 1/176 + 1/176 + ……….n times 1/R = n/176 or R= 176/n Ω By Ohm’s law R=V/I 176/n = 220/5 n= (176 x 5)/220 = 4 13. Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. WebJun 24, 2024 · How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Answer: Let the number of 176 Ω resistors required to be connected in parallel to carry 5 A current on a 220 V line be n. Thus, four resistors of 176 Ω (in parallel) are required to carry 5 A on a 220 V line. Question 86. WebThis tool was designed to help you quickly calculate the equivalent resistance of up to 6 resistors connected in parallel. To use it, just specify how many parallel resistors there are and the resistance value for each one. If you have more than 6 resistors, simply use the calculator to determine the equivalent resistance of the first 6 ... cummings joseph carr aif photos 60001

How many 176 ? resistors (in parallel) are required to carry 5 A

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How many 176 resistors

How Many 176 ω Resistors (In Parallel) Are Required to Carry 5 a …

WebTherefore, 4 resistors of 176Ω ( in parallel) are required to carry 5 A on a 220 V line Suggest Corrections 18 Similar questions Q. A resistor has a resistance of 176 ohms. how many of these resistor should be connected in parallel so that their combination draws a current of 5 ampere from a 220 volt supply line? Q. WebHow many 176 resistors (in parallel) are required to carry 5 A on 220 V line? Expert's answer Download Answer Need a fast expert's response? Submit order and get a quick answer at …

How many 176 resistors

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WebJan 14, 2024 · Resistors are denoted by any label beginning with the letter “R”. This particular circuit board is a computer accessory called a “modem,” which allows digital information transfer over telephone lines. There are … Web(a) Resistance, R ∝ l R ∝ ⇒ R ∝ R = 10Ω (or) R = ρ (i) Resistance is directly proportional to the length of the conductor. If length of nichrome wire (l) is doubled its resistance also gets doubled. ∴ R’, new resistance = 20 Ω (ii) The resistance of the wire is inversely proportional to the square of its diameter.

WebApr 29, 2024 · Q 10: How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? From Ohm’s law, ∴four resistors of 176 Ω are required to draw the given amount of current. ... How many resistors are connected in parallel in a circuit? Three resistor of 10 Ω , 20 Ω , and 30 Ω are connected in parallel in a circuit. ... WebStep 1: List the Given Data Considering the equation as, R = V I R = V I Here, Voltage, V = 220 V Current, I = 5A R = Equivalent Resistance of Combination Step 2: Calculation of the …

WebApr 30, 2024 · 4 Resistors are required. Step-by-step explanation: Given: Volts = 220 Volts. Current = 5 Ampere. Resistance of each resistor, R = 176 Ohms. No of resistors = n. We know that: v = RpI. ∴ ∵ . Taking N to the other side we … WebMar 16, 2024 · Show how you would connect three resistors, each of resistance 6 Ω, so that the combination has a resistance of (i) 9 Ω, (ii) 4 Ω. Note:- If all 3 resistance were different, we would have 8 cases check Q4 Page 216 Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 minute class for ₹ 499 ₹ 299 Transcript

WebTo calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: N = R_desired / R_single Where N is the …

eastwest philippines online bankingWebQuestion How many 176 ohm resistors are required to carry 5A on 220V line Solution Voltage= 220V Current = 5A R=V/I Therefore, R = V/I = 220/5 = 44ohm Resistance= 44ohm … cummings jewelry designWeb1 R = x× 1 (176) 1 R = x × 1 ( 176) R = 176 x 176 x. Now, as per Ohm’s Law, we get, V I = 176 x V I = 176 x. ⇒ x = 176×5 220 = 4 x = 176 × 5 220 = 4. Hence, in order to draw the required amount of current, four 176 Ω resistors will be needed. Related Questions: east west placement cebuWebMar 30, 2024 · NCERT Question 10 How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Current = I = 5 A Potential difference = V = 220 V Resistance of … cummings jewish centre for seniorsWebJun 17, 2016 · Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. 1/44 = 1/176 + 1/176 + 1/176 .....χ times. 1/44 = x / 176 => x = 176/ 44 => x = 4. Therefore, 4 resistors of 176 Ω are required to draw the given amount of current. I hope, this will help you___ . Thank you east west pipeline limitedWebMar 28, 2024 · Expert Answer let us assume there is n number of resistor required. since all the resistors are connected in parallel connection so the equivalence resistance = R = … east-west physio jakartaWebMar 29, 2024 · Judge the equivalent resistance when the following are connected in parallel: (a) 1Ω, and 106 Ω (b) 1 Ω, and 103 Ω and 106 Ω Answer: (a) 1 ohm and 10 6 times ohm R 1 = 1 ohm R 2 = 10 6 times = 1000000 ohm Total resistance (parallel) 1/R = 1/R 1 + 1/R 2 = 1/1 + 1/1000000 = 1000000 + 1 /1000000 = 1000000/ 1000000 1/R = 1/1 ohm (approx.) eastwest ph login